Respuesta :
Answer: The number of moles of [tex]Na_2SO_4[/tex] is 0.05 moles.
Explanation:
To calculate the molarity of solution, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}[/tex]
We are given:
Molarity of solution = 0.10 mol/L
Volume of solution = 1 L
Putting values in above equation, we get:
[tex]0.10mol/L=\frac{\text{Moles of sodium}}{1.0L}\\\\\text{Moles of sodium}=0.10mol[/tex]
The chemical reaction for the ionization of sodium sulfate follows the equation:
[tex]Na_2SO_4(s)\rightarrow 2Na^+(aq.)+SO_4^{2-}(aq.)[/tex]
By Stoichiometry of the reaction:
2 moles of sodium ions are produced by 1 mole of sodium sulfate
So, 0.10 moles of sodium ions will be produced by = [tex]\frac{1}{2}\times 0.1=0.05moles[/tex] of sodium sulfate.
Hence, the number of moles of [tex]Na_2SO_4[/tex] is 0.05 moles.
Answer:
Number of moles of [tex]Na_2SO_4[/tex] are required to make 1.0 L of solution is 0.05 mole.
Explanation:
Given:
[tex]Na_2SO_4(s) \ gives\ 2Na+(aq) + SO_4^2- (aq)[/tex]
Na concentration=0.10 M.
To find
The number of moles of [tex]Na_2SO_4[/tex] which required to make 1.0 L of solution.
To find the mole value,using the molarity formula:
Molarity
[tex]$=\frac{\text { Moles of solute }}{\text { Volume of solution (in L) }}$[/tex]
As we have to find the moles of the solute but we know the molarity so,
Molarity of sodium is 0.10 M.
Therefore,
[tex]$0.10 \mathrm{~mol} =\frac{\text { Moles of sodium }}{1.0 }$[/tex]
Simplified we get,
Moles of sodium is 0.10 M.
As we know that, 2 moles of sodium ions are formed by 1 mole of sodium sulfate
Divide the moles of sodium by 2,
[tex]=0.10/2[/tex]
[tex]=0.5\ mole[/tex]
Learn more about molarity, refer:
- https://brainly.com/question/19943363
