Question

please answer asap need by Wednesday morning

Calculate the pH of 0.16M CH3COOH which has Ka = 1.74 x 10-5 mol dm-3

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Answer 1

Answer:

5.555.

Explanation:

∵ pH = - log[H⁺],

[H⁺] for weak acids = √Ka.C.

Ka for CH₃COOH = 1.74 x 10⁻⁵, C = 0.16 M.

∴ [H⁺] = √Ka.C = √(1.74 x 10⁻⁵)(0.16 M) = 2.784 x 10⁻⁶ M.

∴ pH = - log[H⁺] = - log(2.784 x 10⁻⁶ M) = 5.555.