What is the standard form equation of the line shown below?
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Answer:
x - 2y = - 1
Step-by-step explanation:
The equation of a line in standard form is
Ax + By = C ( A is a positive integer and B, C are integers )
Obtain the equation in slope- intercept form
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (- 3, - 1) and (x₂, y₂ ) = (3, 2) ← 2 points on the line
m = [tex]\frac{2+1}{3+3}[/tex] = [tex]\frac{3}{6}[/tex] = [tex]\frac{1}{2}[/tex]
y = [tex]\frac{1}{2}[/tex] x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (3, 2), then
2 = [tex]\frac{3}{2}[/tex] + c ⇒ c = [tex]\frac{1}{2}[/tex]
y = [tex]\frac{1}{2}[/tex] x + [tex]\frac{1}{2}[/tex] ← in slope- intercept form
Multiply all terms by 2
2y = x + 1 ( subtract 2y from both sides )
0 = x - 2y + 1 ( subtract 1 from both sides )
- 1 = x - 2y , that is
x - 2y = - 1 ← in standard form