What is the surface area of the regular pyramid below

Answer:
Step-by-step explanation:
We have the square in the base and four triangles on the lateral surface.
The formula of an area of a square:
[tex]A_{\square}=a^2[/tex]
a - side lenght
We have a = 16. Substitute:
[tex]A_{\square}=16^2=256[/tex]
The formula of an area of a triangle:
[tex]A_{\triangle}=\dfrac{bh}{2}[/tex]
b - base
h - height
We have b = 16 and h = 19. Substitute:
[tex]A_{\triangle}=\dfrac{(16)(19)}{2}=152[/tex]
The Surface Area:
[tex]S.A.=A_{\square}+4_{\triangle}[/tex]
Substitute:
[tex]S.A.=256+4(152)=256+608=864[/tex]
Answer: it C. 864 units²
Step-by-step explanation: I just did it