Answer:
[tex]\boxed{\textbf{46 dm}^{3}}[/tex]
Explanation:
The pressure is constant, so we can use Charles' Law to calculate the volume.
[tex]\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}[/tex]
Data:
V₁ = 40 dm³; T₁ = 5 °C
V₂ = ?; T₂ = 50 °C
Calculations:
(a) Convert temperature to kelvins
T₁ = ( 5 + 273.15) = 278.15 K
T₂ = (50 + 273.15) = 323.15 K
(b) Calculate the volume
[tex]\dfrac{40}{278.15} = \dfrac{V_{2}}{323.15}\\\\{ V_{2}} = 40 \times \dfrac{323.15}{278.15}\\\\V_{2} = 40 \times 1.162 = \boxed{\textbf{46 dm}^{3}}[/tex]
