Answer:
ALL are TRUE.
The mean for Group A is less than the mean for Group B.
The median for Group A is less than the median for Group B.
The mode for Group A is less than the mode for Group B.
The median for Group A is 2.
The median for Group B is 3.
Step-by-step explanation:
To answer this, you need to know how to determine the mean, mode and median. You can determine this in your dot plots. Each dot on a number tells you how many times it occurs in the set of data.
Mean is also known as the average. It is the sum of all values divided by the number of values. So all you need to do is add up the values and divide it by how many values was given per group.
GROUP A:
[tex]\dfrac{1+1+1+1+1+2+2+2+2+3}{10}= \dfrac{16}{10}=1.6[/tex]
GROUP B:
[tex]\dfrac{1+1+1+2+2+3+3+3+3+5}{10}=\dfrac{24}{10}=2.4[/tex]
Mode is the value that occurs the most in a set of data. So in this case, you just need to find the number with the most dots in each group to find the mode of each group.
Median is the value you find in the middle of the data when you sort it out. In a set of data that is odd, just get the middle value. If you have an even set of numbers, then you take the two middle values and divide it by two.
(In your problem you have 10 values, so you would add the 5th and 6th values and divide it by two. )
Let's take your problem as an example.
Group A Vs Group B
MEAN:
MEAN MODE MEDIAN
GROUP A 1.6 1 1.5 ≅ 2
GROUP B 2.4 3 2.5 ≅ 3
So based on the data given above, the answer would be:
All are TRUE
The mean for Group A is less than the mean for Group B.
The median for Group A is less than the median for Group B.
The mode for Group A is less than the mode for Group B.
The median for Group A is 2.
The median for Group B is 3.
