Answer:
5.63 mol.
Explanation:
3NO₂(s) + H₂O(l) → 2HNO₃(aq) + NO(g),
It is clear that 3 mol of NO₂ reacts with 1 mol of H₂O to produce 2 mol of HNO₃ and 1 mol of NO.
Water is present as an excess reactant and NO₂ is limiting reactant.
3 mol of NO₂ produces → 2 mol of HNO₃, from stichiometry.
8.44 mol of NO₂ produces → ??? mol of HNO₃.
∴ The no. of moles of HNO₃ are formed = (8.44 mol)(2 mol)/(3 mol) = 5.63 mol.
Considering the definition of reaction stoichiometry, 5.63 moles of HNO₃ are formed from 8.44 moles of NO₂ if there is plenty of water present.
The balanced reaction is:
3 NO₂ + H₂O → 2 HNO₃ + NO
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
So, you can apply the following rule of three: if by reaction stoichiometry 3 moles of NO₂ produce 2 moles of HNO₃, 8.44 moles of NO₂ produces how many moles of HNO₃?
[tex]amount of moles of HNO_{3} =\frac{8.44 moles of NO_{2}x2 moles of HNO_{3}}{3 moles of NO_{2}}[/tex]
amount of moles of HNO₃= 5.63 moles
Finally, 5.63 moles of HNO₃ are formed from 8.44 moles of NO₂ if there is plenty of water present.
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