Question

an object is kept at 45 m high and how much time will it take to reach the ground​

Answer 1

Answer:

t=3.0289s (Assuming a=9.81)

t=3s (Assuming a=10)

Explanation:

a=9.81

u=0

s=45

$s = ut + \frac{1}{2} a{t}^{2}$

$45 =0 + \frac{1}{2} (9.81) {t}^{2}$

t = 3.0289s