The area of a triangle is half the multiplication of the base and the height.
So, if the smaller triangle has height 6 cm and base 2 cm, its are is
[tex]\dfrac{6\times 2}{2}=6[/tex]
Similarly, if the height of the larger triangle is 9 cm, and its base is 3 cm, its area is
[tex]\dfrac{9\times 3}{2}=\dfrac{27}{2}[/tex]
So, the total area is
[tex]6+\dfrac{27}{2} = \dfrac{12}{2}+\dfrac{27}{2}=\dfrac{39}{2}[/tex]