Question

A quadratic equation of the form 0=ax^2+bx+c has a discriminate value of -16. How many real number solutions does this equation have?

Answer 1

Answer:

0

Step-by-step explanation:

The disciminant $\Delta$ tells you how many real solutions a quadratic equation has, depending on its sign:

$\Delta>0\implies\text{2 solutions}\\\Delta=0\implies\text{1 solution}\\\Delta<0\implies\text{no solutions}$

Answer 2

ANSWER

0

EXPLANATION

The discriminant of a quadratic equation in the form

$a {x}^{2} + bx + c = 0$

is given by

$D = {b}^{2} - 4ac$

The discriminant of a quadratic equation tells us the nature of the roots of that quadratic equation.

If the discriminant is negative, the equation has no real roots.

If the discriminant us positive, the equation has two real roots.

If the discriminant is zero, the equation has a repeated root.

Since the discriminant is -6, the equation has no real roots.

In other words, the number of real roots is 0.