A) [tex]3.6\cdot 10^5 J[/tex]
The power used by an object is defined as
[tex]P=\frac{E}{t}[/tex]
where
E is the energy used
t is the time elapsed
In this problem, we have
P = 100 W is the power of the light bulb
t = 1 h = 3600 s is the time elapsed
Solving for E, we find the amount of energy used by the light bulb:
[tex]E=Pt = (100 W)(3600 s)=3.6\cdot 10^5 J[/tex]
B) [tex]1.1 \cdot 10^2 m/s[/tex]
The kinetic energy of an object is given by
[tex]K=\frac{1}{2}mv^2[/tex]
where
m is the mass
v is the speed of the object
In this problem, we have a man of mass
m = 65 kg
we want its kinetic energy to be
[tex]E=3.6\cdot 10^5 J[/tex]
Therefore, we can calculate its speed from the previous formula:
[tex]v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(3.6\cdot 10^5 J)}{65 kg}}=105.2 m/s = 1.1 \cdot 10^2 m/s[/tex]