For this case we must solve the following equation:
[tex]\frac {2} {3} x- \frac {1} {2} = \frac {1} {3} + \frac {5} {6} x[/tex]
Subtract [tex]\frac {5} {6} x[/tex] on both sides of the equation:
[tex]\frac {2} {3} x- \frac {5} {6} x- \frac {1} {2} = \frac {1} {3}[/tex]
We add [tex]\frac {1} {2}[/tex] to both sides of the equation:
[tex]\frac {2} {3} x- \frac {5} {6} x = \frac {1} {3} + \frac {1} {2}\\\frac {12-15} {18} x = \frac {2 + 3} {6}\\\frac {-3} {18} x = \frac {5} {6}\\- \frac {1} {6} x = \frac {5} {6}\\[/tex]
We multiply by 6 on both sides of the equation:
[tex]-x = 5[/tex]
We multiply by -1 on both sides of the equation:
[tex]x = -5[/tex]
Answer:
[tex]x = -5[/tex]
