Answer:
add 7.5L of water
Explanation:
M1×V1=M2×V2
M is molarity, V is volume
0.7 × 10 = 0.4 × V2
V2= 17.5L
vol. of water to add= 17.5 - 10 = 7.5L
The volume which is required to prepare 0.4M lemonade is 17.5L.
Required volume of the solution will be calculated by using the below equation as:
M₁V₁ = M₂V₂, where
M₁ & V₁ are the molarity and volume of initial lemonade.
M₂ & V₂ are the molarity and volume of final prepared lemonade.
On putting all values from the question, we get
V₂ = (0.7)(10) / (0.4) = 17.5 L
Hence required volume of final lemonade is 17.5 L.
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