Question

In a school, 40% of the students play tennis, 24% of the students play baseball, and 58% of the students play neither tennis nor baseball. If you pick a student at random, what is the probability that the student plays both tennis and baseball?

Answer 1

Answer:

0.22

Step-by-step explanation:

If 58% of the students play neither tennis nor baseball, then;

100 - 58 = 42% play tennis, baseball or both sports. Now,

Pr ( tennis ∪ baseball) = Pr ( tennis) + Pr ( baseball) - Pr ( tennis ∩ baseball)

42% = 40% + 24% -  Pr ( tennis ∩ baseball)

Pr ( tennis ∩ baseball) = 40 + 24 - 42

Pr ( tennis ∩ baseball) = 22%

Therefore, If you pick a student at random the probability that the student plays both tennis and baseball is 0.22