Question

This figure is made up of a triangle and a semicircle.

What is the area of the figure?

Use 3.14 for π

.

Enter your answer, as a decimal, in the box.
units²

Answer 1

Separate the shape into two figures, a semi circle and a rectangle. Find the area of each and add.

See attached picture:

Answer 2

Answer:  The area of the figure is 29.13 sq. units.

Step-by-step explanation:  We are given to find the area of he figure shown in the graph.

The figure is made up of a triangle and a semi-circle.

Let us divide the figure into two parts, triangle ABC with base BC and altitude AD and the circle with diameter BC as shown in the attached image below.

From the graph, we note that

AD = 5 units  and  BC = 6 units.

Since BC is the diameter of the semicircle, so its radius will be

$r=\dfrac{1}{2}\times BC=\drac{1}{2}\times6=3~\textup{units}.$

So, the area of the semicircle is given by

$A_{sc}=\dfrac{\pi r^2}{2}=3.14\times \dfrac{3^2}{2}=3.14\times 4.5=14.13~\textup{sq. units}.$

Also, the area of the triangle ABC is given by

$A_t=\dfrac{1}{2}\times AD\times BC=\dfrac{1}{2}\times5\times6=15~\textup{sq. units}.$

Therefore, the total area of the figure will be

$A=A_{sc}+A_t=14.13+15=29.13~\textup{sq. units}.$

Thus, the area of the figure is 29.13 sq. units.