Respuesta :
Surface area of the prism= surface area of the base + surface area of the two triangles + surface area of the two rectangles.
Surface area of the base=(3 yd * 7 yd)=21 yd².
Surface area of the two triangles=2*(3 yd * 4 yd)/2=12 yd².
Surface area of the two rectangles=(7 yd * 5 yd) + (7 yd * 4yd)=35 yd² + 28 yd²=
=63 yd²
Surface of the prism=21 yd² + 12 yd² + 63 yd²=96 yd²
Remember:
surface area of a triangle=(base * height)/2
surface area of a rectangle=base * height.
Answer: C.96 yd²
Surface area of the base=(3 yd * 7 yd)=21 yd².
Surface area of the two triangles=2*(3 yd * 4 yd)/2=12 yd².
Surface area of the two rectangles=(7 yd * 5 yd) + (7 yd * 4yd)=35 yd² + 28 yd²=
=63 yd²
Surface of the prism=21 yd² + 12 yd² + 63 yd²=96 yd²
Remember:
surface area of a triangle=(base * height)/2
surface area of a rectangle=base * height.
Answer: C.96 yd²