Question

The specific heat of carbon is 0.71 j/(g C) how much energy is given off as a 2 gram piece of graphite cools from 120 to 20 C

Answer 1

Answer:

-142 joules ( or -100 joules when accounting for significant figures)

Explanation:

q = m c delta T

q = (.71)(2)(20 - 120)

q = (.71)(2)(-100)

q = -142 joules

Answer 2

The specific heat of carbon is 0.71 J/g.°C then the amount of energy which is given off as a 2 gram piece of graphite cools from 120°C to 20°C is -142 Joules.

How do we calculate the absorbed heat?

Amount of absorbed heat by any substance will be calculated by using the below equation:

Q = mcΔT, where

• m = mass of graphite = 2g
• c = specific heat of graphite = 0.71 J/g. degree C
• ΔT = change in temperature = 20 - 120 = -100 degree C

On putting all these values, we get

Q = (2)(0.71)(-100) = -142 J

Hence, -142 Joules is the value of given off energy.

To know more about absorbed heat, visit the below link:
https://brainly.com/question/8828503

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