Question

How much heat is absorbed by a 45g iron skillet when its temperature rises from 6oC to 21oC?

Answer 1

Answer: 299.7 J

Explanation:

The heat (thermal energy) absorbed by the iron skillet can be found using the following equation:

$Q=m.C.\Delta T$   (1)

Where:

$Q$ is the heat

$m=45 g$ is the mass of the element (iron in this case)

$C$ is the specific heat capacity of the material. In the case of iron is $C=0.444\frac{J}{g\°C}$

$\Delta T=T_{f}-T_{i}=21\°C - 6\°C= 15\°C$ is the variation in temperature

Knowing this, lets rewrite (1) with these values:

$Q=(45 g)(0.444\frac{J}{g\°C})(15\°C)$  (2)

Finally:

$Q=299.7 J$  

Answer 2

Answer:

299.7 J

Explanation: