Answer:
[tex]\boxed{\text{B.}}[/tex]
Explanation:
B.
[tex]\rm C$_7$H_{16}$ + 11O$_2$ $\longrightarrow \,$ 7CO$_2$ + 8H$_2$O[/tex]
BALANCED. 7C, 16H, and 22O on each side of equation.
A.
[tex]\rm C$_7$H$_{16}$ + 5O$_2$ $\longrightarrow \,\rm 6CO$_2$ + 4H$_2$O[/tex]
NOT BALANCED. 7C on left and 6C on right.
C.
[tex]\rm C$_7$H$_{16}$ + 14O$_2$ $\longrightarrow \,$ 7CO$_2$ + 5H$_2$O[/tex]
NOT BALANCED. 16H on left and 10H on right.
D.
[tex]\rm C$_7$H$_{16}$ + 22O$_2$ $\longrightarrow \, $ 14CO$_2$ + 16H$_2$O[/tex]
NOT BALANCED. 7C on left and 14C on right.
