Question

find the solution of 4x^2-4x-1=0

Answer 1

$4x^{2} -4x - 1 = 0$

To solve for the zeros you can use the quadratic formula:

$\frac{-b plus/minus\sqrt{b^{2}-4ac } }{2a}$

a = 4

b = -4

c = -1

$\frac{-(-4) plus/minus\sqrt{(-4)^{2}-4(4)(-1) } }{2(4)}$

$\frac{4 plus/minus\sqrt{16+16 } }{8}$

$\frac{4plus/minus\sqrt{32} }{8}$

$\frac{4plus/minus4\sqrt{2 } }{8}$

$\frac{1 plus/minus\sqrt{2} }{2}$

Hope this helped!

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