Question

Please help! :)

Solve for x to the nearest tenth.

X^2+x-5=0

Answer 1

Answer:

1.8, -2.8

Step-by-step explanation:

1.8, -2.8 in decimal form rounded to the nearest tenth.

In quadratic form its originally $x=\frac{-1+\sqrt{21} }{2} ,\frac{-1-\sqrt{21} }{2}$

Hope this helps