Question

What are the zeros of the function? f(x)=3x^2−24x+36 Enter your answers in the boxes. The zeros of f(x) are and

Answer 1

$

f(x)=3x^2-24x+36 \\

0=3(x-2)(x-6) \\

0=(x-2)(x-6)

$

There will be 2 solutions.

$

x-2=0\Longrightarrow\boxed{x_1=2} \\

x-6=0\Longrightarrow\boxed{x_2=6}

$

Hope this helps.

r3t40