For this case we have that by definition, the equation of a line in the slope-intersection form is given by:
[tex]y = mx + b[/tex]
Where:
m: It's the slope
b: It is the cut point with the y axis.
We look for two points through which the line passes to find the slope:
[tex](x1, y1) = (2,2)\\(x2, y2) = (0, -4)[/tex]
[tex]m = \frac {y2-y1} {x2-x1} = \frac {-4-2} {0-2} = \frac {-6} {- 2} = 3[/tex]
So, the line is:
[tex]y = 3x + b[/tex]
We have "b" replacing any of the points:
[tex]-4 = 3 (0) + b\\-4 = b[/tex]
Finally, the equation is:
[tex]y = 3x-4[/tex]
Answer:
[tex]y = 3x-4[/tex]