Question

solve the inequality |2h-3| >1

Answer 1

Answer:

$\large\boxed{h>2\ \vee\ h<1\to h\in(-\infty,\ 1)\ \cup\ (2,\ \infty)}$

Step-by-step explanation:

$|2h-3|>1\iff2h-3>1\ \vee\ 2h-3<-1\qquad\text{add 3 to both sides}\\\\2h>4\ \vee\ 2h<2\qquad\text{divide both sides by 2}\\\\h>2\ \vee\ h<1\to h\in(-\infty,\ 1)\ \cup\ (2,\ \infty)$