Question

what is the total number of moles present in a 526.0-gram sample of NaNCO3(s)?

Answer 1

Answer:

6.26 mol.

Explanation:

• We have the relation:

no. of moles (n) = mass/molar mass.

mass of NaHCO₃ = 526.0 g, Molar mass of NaHCO₃ = 84.007 g/mol

∴ no. of moles (n) of NaHCO₃ = mass/molar mass = (526.0 g)/(84.007 g/mol) = 6.26 mol.