Question

SERIOUSLY HELP! A manufacturer is designing a two-wheeled cart that can maneuver in tight spaces. On one test model, the wheel placement (center) and radius are modeled by the equation (x+1.5)^2 + (y-2)^2 = 4

Answer 1

Answer

Center = (-1.5, -1) and radius is 3.

Answer 2

The Center = (-1.5, 2) and radius is 2 of the equation  (x+1.5)^2 + (y-2)^2 = 4.

We have given that,

A manufacturer is designing a two-wheeled cart that can maneuver in tight spaces.

On one test model, the wheel placement and radius are modeled by the equation (x+1.5)^2 + (y-2)^2 = 4.

We have to determine the center and radius of the given equation.

What is the standard form of the circle?

The standard form for the equation of a circle is $(x-h)^2+(y-k)^2=r^2.$

The center is (h,k) and the radius measures r units.

Compare the given equation with the standard form of the equation so we get,

radius=4=(2)^2=2

center(h,k)=(-1.5,2)

Therefore, the Center = (-1.5, 2) and radius is 2 of the equation  (x+1.5)^2 + (y-2)^2 = 4.

To learn more about the standard form of the circle visit:

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