Respuesta :

ANSWER

B.

[tex](f + g)(x) = {x}^{3} + x- 715[/tex]

EXPLANATION

The given functions are:

[tex]f(x) = \sqrt{ {x}^{2} + 28x + 196} [/tex]

This is the same as

[tex]f(x) = \sqrt{ {(x + 14)}^{2} } [/tex]

[tex]f(x) = x + 14[/tex]

and

[tex]g(x) = {x}^{3} - 729[/tex]

[tex](f + g)(x) = f(x) + g(x)[/tex]

[tex](f + g)(x) = x + 14 + {x}^{3} - 729[/tex]

[tex](f + g)(x) = {x}^{3} + x- 715[/tex]

The correct answer is B

Answer:

B.

Step-by-step explanation:

[tex]= f(x) + g(x)\\= \sqrt{x^{2} +28x+196} +x^{3} -729\\factor (x^{2} +28x+196) to ((x+14)^{2})\\= \sqrt{(x+14)^{2} } +x^{3} -729\\= x+14+x^{3} -729\\=x^{3} +x-715[/tex]

ACCESS MORE