Question

If a baseball player hits a baseball from 4 feet off the ground with an initial velocity of 64 feet per second, how long will it take the baseball to hit the ground? Use the equation h = −16t2 + 4t + 4. Round your answer to the nearest hundredth.

0.36
0.39
0.61
0.65

Answer 1

Answer:

0.64 seconds.

Step-by-step explanation:

When it hits the ground h(t) = 0.

0 = -16t^2 + 4t + 4

-4(4t^2 - t -1) = 0

t = [-(-1) +/- sqrt (1 - 4*4*-1)] / 8)

t = 0.64, -0.39

answer is 0.64 seconds.

Answer 2

it will take the baseball 0.64 seconds to hit the ground.

The equation representing the height is:

h = -16t² + 4t + 4

When the baseball hits the ground, the height will be 0. That is,h =0

Substitute h =0 into the equation above

0 = -16t² + 4t + 4

Rearrange the given equation to be:

16t² - 4t - 4 = 0

Solving the quadratic equation above:

t = -0.39 and 0.64

Since time cannot be negative, it will take the baseball 0.64 seconds to hit the ground.

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