Question

factor completely, 128x 2 +96xy + 18y 2

Answer 1

Answer:

$2(8x+3y)^2)$

Step-by-step explanation:

The given expression is $128x^2+96xy+18y^2$.

We factor the GCF to get:

$2(64x^2+48xy+9y^2)$

This can be rewritten as:

$2[(8x)^2+2(3\times8)xy+(3y)^2]$

We can observe that the quadratic trinomial is a perfect square)

$2(8x+3y)^2)$

Therefore the completely factored form of the given trinomial is $2(8x+3y)^2)$