What is the value of the natural logarithm when x = 0.5 is rounded to the nearest
hundredth?

The value of the natural logarithm when x = 0.5 is rounded to the nearest hundredth is -0.69. So option B is correct.
When you raise a number with an exponent, there comes a result.
Let's say you get
a^b = c
Then, you can write 'b' in terms of 'a' and 'c' using a logarithm as follows
[tex]b = \log_a(c)[/tex]
'a' is called the base of this log function. We say that 'b' is the logarithm of 'c' to base 'a'
Since x is lesser than 1, then the value of its natural logarithm must be negative.
The natural logarithm is a transcendental function and an irrational number, then it can be estimated by approximations.
ln ( 0.5) = -0.69
The value of the natural logarithm when x = 0.5 is rounded to the nearest hundredth is -0.69. So option B is correct.
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