A basketball is thrown upwards. The height f(t), in feet, of the basketball at time t, in seconds, is given by the following function: f(t) = −16t2 + 44t + 12 Which of the following is a reasonable domain of the graph of the function when the basketball falls from its maximum height to the ground?

Respuesta :

Answer:

Reasonable domain is [1.375,3].

Step-by-step explanation:

Given function is [tex]f\left(t\right)=-16t^2+44t+12[/tex].

Now we need to find about what is the reasonable domain of the graph of the function [tex]f\left(t\right)=-16t^2+44t+12[/tex] when the basketball falls from its maximum height to the ground.

Compare with [tex]at^2+bt+c[/tex], we get a=-16 and b=44

then t-coordinate of vertex [tex]t=-\frac{b}{2a}=-\frac{44}{2\left(-16\right)}=1.375[/tex]

Then that means maximum height of the ball occurs when time t=1.375 seconds.

Now let's find time when ball falls on ground so set f(t)=0

[tex]f\left(t\right)=-16t^2+44t+12[/tex]

[tex]-16t^2+44t+12=0[/tex]

[tex]4t^2-11t-3=0[/tex]

[tex]\left(4t+1\right)\left(t-3\right)=0[/tex]

[tex]4t+1=0[/tex] or [tex]t-3=0[/tex]

[tex]4t=-1[/tex] or [tex]t=3[/tex]

[tex]t=-0.25[/tex] or [tex]t=3[/tex]

Time can't be negative so we use t=3 only

Hence reasonable domain is [1.375,3].

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