Question

What is the axis of symmetry for f(x) = x2 + 4x + 6

Answer 1

Answer:

x = -2

Step-by-step explanation:

In order to find the axis of symmetry, we will have to find the x-value of the vertex.

Vertex = (-b/2a, f(-b/2a))

In x² + 4x + 6,

a = 1 , b = 4 , c = 6

Vertex = (-4/2,f(-4/2))

Vertex = (-2,f(-2))

We have found the x-value of the vertex which is -2.

Hence, line/axis of symmetry is x = -2

Answer 2

The axis of symmetry for f(x) = $x^2 + 4x + 6$  is -2.

Given that,

• The equation is  f(x) = $x^2 + 4x + 6$.
• Here we need to find the axis of symmetry.

Based on the above information, the calculation is as follows:

Here we have to determine the x-value of the vertex.

$Vertex = (-b\div 2a, f(-b\div 2a))$

Now as per the given equation i.e $x^2 + 4x + 6$

Here,

a = 1 , b = 4 , c = 6

Now  

$Vertex = (-4\div 2,f(-4\div 2))$

 = (-2,f(-2))

= -2

Therefore we can conclude that the axis of symmetry for f(x) = $x^2 + 4x + 6$  is -2.

Learn more: brainly.com/question/2491015