Answer:
7
Step-by-step explanation:
Considered that the spinner is spun twice, we have 16 different combinations:
2 2
2 3
2 4
2 9
3 2
3 3
3 4
3 9
4 2
4 3
4 4
4 9
9 2
9 3
9 4
9 9
I have written in bold the combinations that contain at least one even number: there are 12 of them.
Now we have to check the product of each of these combinations:
2 x 3 = 6
2 x 9 = 18
3 x 2 = 6
3 x 3 = 9
3 x 4 = 12
3 x 9 = 27
4 x 3 = 12
4 x 9 = 36
9 x 2 = 18
9 x 3 = 27
9 x 4 = 36
9 x 9 = 81
Here I have written in bold the combinations that have a product less than 20: there are 7 of them.
So, 7 out of 16 outcomes have a product less than 20 and contain at least one even number.
Answer with Step-by-step explanation:
On spinning the spinner twice,we have 16 different outcomes:.
We write the outcomes with their product:
Product
2 2 4
2 3 6
2 4 8
2 9 18
3 2 6
3 3 9
3 4 12
3 9 27
4 2 8
4 3 12
4 4 16
4 9 36
9 2 18
9 3 27
9 4 36
9 9 81
outcomes have a product less than 20 and contain at least one even number are in bold letters.
Hence, outcomes have a product less than 20 and contain at least one even number are:
10
