Respuesta :
Answer: 1,7 and 1,5 on coefficient
Step-by-step explanation:
Equation at the end of step 1 :
(((5•(x4))+(x3))+3x2)-7
Step 2 :
Equation at the end of step 2 :
((5x4 + x3) + 3x2) - 7
Step 3 :
Checking for a perfect cube :
3.1 5x4+x3+3x2-7 is not a perfect cube
Trying to factor by pulling out :
3.2 Factoring: 5x4+x3+3x2-7
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 3x2-7
Group 2: 5x4+x3
Pull out from each group separately :
Group 1: (3x2-7) • (1)
Group 2: (5x+1) • (x3)
3.3 Find roots (zeroes) of : F(x) = 5x4+x3+3x2-7
Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 5 and the Trailing Constant is -7.
The factor(s) are:
of the Leading Coefficient : 1,5
of the Trailing Constant : 1 ,7
The factor of the constant is [tex]\rm (x+1) (5x^3-4x^2+7x-7) =0\\\\[/tex].
Given
Expression; [tex]\rm 5x^4+x^3+3x^2-7[/tex]
What is the leading coefficient?
The leading coefficient of the polynomial of the term has the highest degree of the polynomial.
The factors of the constant term;
[tex]\rm 5x^4+x^3+3x^2-7=0\\\\ 5x^4-4x^3+7x^2-7x+5x^3-4x^2+7x-7=0\\\\(x+1) (5x^3-4x^2+7x-7) =0\\\\[/tex]
Hence, the factor of the constant is [tex]\rm (x+1) (5x^3-4x^2+7x-7) =0\\\\[/tex].
To know more about the Leading coefficient click the link given below.
https://brainly.com/question/13577114
