Find the value of x. Round to the nearest tenth.
PLEASE HELP ME!!

Answer:
Step-by-step explanation:
Use the Pythagorean theorem:
[tex]leg^2+leg^2=hypotenuse^2[/tex]
We have
[tex]leg=x,\ leg=15.6cm:2=7.8cm,\ hypotenuse=8.8cm[/tex]
Substitute:
[tex]x^2+7.8^2=8.8^2[/tex]
[tex]x^2+60.84=77.44[/tex] subtract 60.84 from both sides
[tex]x^2=16.6\to x=\sqrt{16.6}\\\\x\approx4.1\ cm[/tex]