Respuesta :

[tex]\bf \textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh~~ \begin{cases} b=base\\ h=height\\ \cline{1-1} A=8\\ h=4 \end{cases}\implies 8=\cfrac{1}{2}b(4)\implies 8=2b\implies \cfrac{8}{2}=b\implies 4=b[/tex]

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