[tex]\bf \textit{surface area of a cone}\\\\ SA=\pi r\sqrt{r^2+h^2}+\pi r^2~~ \begin{cases} r=radius\\ h=height\\ \cline{1-1} r=9\\ h=13 \end{cases}\implies SA=\pi (9)\sqrt{9^2+13^2}+\pi (9)^2 \\\\\\ SA=9\pi \sqrt{250}+81\pi \implies SA=9\pi (\sqrt{250}+9)\implies SA\approx 701.53[/tex]
