Respuesta :

Step-by-step Answer:

To answer this question, we can simplify each expression and then substitute n.  

If you use a calculator, you can just plug-in n=2 to see which one is the greatest.

A. n^5*n^2/n^4 = n^(5+2-4) = n^3

B. n^2*n^3/n = n^(2+3-1) = n^4

C. (n^2)^3/n = n^(2*3-1) = n^5

D (n^5)^2/n^4 = n^(5*2-4) = n^6

As long as n>1, the higher power n has, the larger is the number.

Therefore (n^5)^2/n^4 = n^(5*2-4) = n^6 is the winner!

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