Answer:
123. [tex]A=lw[/tex], [tex]A=72[/tex]
124. B) 20 square feet
125. C) [tex]\frac{1}{6}[/tex]
126. A) 24 + 12, B) (4*6)+(4*3)
127. 30, 36, 44
Step-by-step explanation:
123. Area = length*width
Substitute '9' for [tex]l[/tex] and '8' for [tex]w[/tex].
[tex]A=(9)(8)[/tex] or [tex]A=(9*8)[/tex]
[tex]9*8=72[/tex], so [tex]A=72[/tex].
124. Using the formula [tex]A=lw[/tex], substitute '5' for [tex]l[/tex] and '4' for [tex]w[/tex].
[tex]A=(5)(4)[/tex] or [tex]A=(5*4)[/tex]
[tex]5*4=20[/tex], so [tex]A=20[/tex].
125. The hexagon was divided into 6 triangles, so each of the triangles is one out of six, one sixth ([tex]\frac{1}{6}[/tex].
126. The lighter rectangle's area is 24 and the darker's is 12 because (4*6) = 24 and (4*3) = 12.
127. For these shapes, I am using the 'subtraction' method (find the area of the shape as if it were a larger rectangle, then subtract the 'blank' spaces).
A(larger rectangle) = [tex]6*7=42[/tex]
A('blank' space) = [tex]3*4=12[/tex]
A(larger rectangle - 'blank' space) = [tex]42-12=30[/tex]
A(larger rectangle) = [tex]8*7=56[/tex]
A('blank' space) = [tex]5*4=20[/tex]
A(larger rectangle - 'blank' space) = [tex]56-20=36[/tex]
A(larger rectangle) = [tex]8*6=48[/tex]
A('blank' space) = [tex]2*1=2[/tex] (there are two of them (both equal), so add them both together) 2 + 2 = 4.
A(larger rectangle - 'blank' space) = [tex]48-4=44[/tex]
