Answer:
[tex]\log (3x)[/tex]
Step-by-step explanation:
The given logarithmic expression is:
[tex]\frac{1}{3}\log(3x)+ \frac{2}{3}\log(3x)[/tex]
This is the same as:
[tex]\frac{1}{3}\log(3x)+ \frac{1}{3}\log(3x)^2[/tex]
[tex]\frac{1}{3}(\log(3x)+ \log(3x)^2)[/tex]
We now apply the product rule to get:
[tex]\frac{1}{3}\log(3x)\times (3x)^2[/tex]
[tex]\frac{1}{3}\log (3x)^3[/tex]
We now apply the power rule to get;
[tex]\frac{3}{3}\log (3x)=\log (3x)[/tex]