Answer:
TU = 8 in
Step-by-step explanation:
If a secant segment and a tangent segment share an
endpoint outside a circle, then the product of the lengths
of the secant segment and its external segment equals
the square of the length of the tangent segment.
So
TU^2 = ST * RT
Given RT = 16 in, ST = 4 in
Plug in to find TU
TU^2 = 4 * 16
TU^2 = 64
TU = 8 in
