In any cyclic quadrilateral, angles opposite one another are supplementary, meaning
[tex]m\angle K+m\angle I=m\angle L+m\angle J=180^\circ[/tex]
and given that [tex]\boxed{m\angle K=64^\circ}[/tex], we have [tex]\boxed{m\angle I=116^\circ}[/tex].
By the inscribed angle theorem,
[tex]m\angle JLK=\dfrac12m\widehat{KJ}[/tex]
[tex]m\angle ILJ=\dfrac12m\widehat{IJ}[/tex]
and since
[tex]m\angle L=m\angle JLK+m\angle ILJ[/tex]
we have
[tex]m\angle L=\dfrac{97^\circ+59^\circ}2\implies\boxed{m\angle L=78^\circ}[/tex]
and it follows that
[tex]m\angle J=180^\circ-m\angle L\implies\boxed{m\angle J=102^\circ}[/tex]