There are 9 students in a class: 2 boys and 7 girls. If the teacher picks a group of 4 at random, what is the probability that everyone in the group is a girl?

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Answer:

28% probability that every student in the group is a girl.

Step-by-step explanation:

In this problem we have independent events, that is, the event "picking a girl" doesn't affect an "picking a boy", also, picking picking a girl doesn't affect the probability of the other subjects.

So, the probability when the first girl is being picked is:

[tex]P_{1}=\frac{7 \ girls}{9 \ students}[/tex]

Because among the total 9 students, there are 7 girls.

Now, after picking one girl, there remains 6 girls and 8 students to be picked. So, the probability of the second girl would be:

[tex]P_{2}=\frac{6 \ girls}{8 \ students}[/tex]

Then, the probability of the third girl:

[tex]P_{3}=\frac{5 \ girls}{7 \ students}[/tex]

The fourth girl probability:

[tex]P_{3}=\frac{4 \ girls}{6 \ students}[/tex]

Therefore, the probability of picking all 4 girls would be the product of each probability, because events are independent (we use product when they are independent):

[tex]P=\frac{7 \ girls}{9 \ students} \times \frac{6 \ girls}{8 \ students} \times \frac{5 \ girls}{7 \ students} \times \frac{4 \ girls}{6 \ students}\\P=\frac{5}{18}=0.28 \ (or \  28\%)[/tex]

Therefore, there's 28% probability that every student in the group is a girl.

The probability that everyone in the group is a girl is 0.2778

How to determine the probability?

The distribution of the students is given as:

Boys = 2

Girls = 7

Total = 9

The selection of the 4 girls at random is:

  • 7 girls from 9 students
  • 6 girls from the remaining 8 students
  • 5 girls from the remaining 7 students
  • 4 girls from the remaining 6 students

So, the probability that all students are girls is:

P = 7/9 * 6/8 * 5/7 * 4/6

Evaluate

P = 0.2778

Hence, the probability that everyone in the group is a girl is 0.2778

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