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Answer:
28% probability that every student in the group is a girl.
Step-by-step explanation:
In this problem we have independent events, that is, the event "picking a girl" doesn't affect an "picking a boy", also, picking picking a girl doesn't affect the probability of the other subjects.
So, the probability when the first girl is being picked is:
[tex]P_{1}=\frac{7 \ girls}{9 \ students}[/tex]
Because among the total 9 students, there are 7 girls.
Now, after picking one girl, there remains 6 girls and 8 students to be picked. So, the probability of the second girl would be:
[tex]P_{2}=\frac{6 \ girls}{8 \ students}[/tex]
Then, the probability of the third girl:
[tex]P_{3}=\frac{5 \ girls}{7 \ students}[/tex]
The fourth girl probability:
[tex]P_{3}=\frac{4 \ girls}{6 \ students}[/tex]
Therefore, the probability of picking all 4 girls would be the product of each probability, because events are independent (we use product when they are independent):
[tex]P=\frac{7 \ girls}{9 \ students} \times \frac{6 \ girls}{8 \ students} \times \frac{5 \ girls}{7 \ students} \times \frac{4 \ girls}{6 \ students}\\P=\frac{5}{18}=0.28 \ (or \ 28\%)[/tex]
Therefore, there's 28% probability that every student in the group is a girl.
The probability that everyone in the group is a girl is 0.2778
How to determine the probability?
The distribution of the students is given as:
Boys = 2
Girls = 7
Total = 9
The selection of the 4 girls at random is:
- 7 girls from 9 students
- 6 girls from the remaining 8 students
- 5 girls from the remaining 7 students
- 4 girls from the remaining 6 students
So, the probability that all students are girls is:
P = 7/9 * 6/8 * 5/7 * 4/6
Evaluate
P = 0.2778
Hence, the probability that everyone in the group is a girl is 0.2778
Read more about probability at:
https://brainly.com/question/251701