How to solve and check my solutions

Answer:
see explanation
Step-by-step explanation:
Subtract [tex]\frac{2}{3x}[/tex] from both sides
[tex]\frac{1}{6}[/tex] = [tex]\frac{4}{3x}[/tex] - [tex]\frac{2}{3x}[/tex] = [tex]\frac{4-2}{3x}[/tex] = [tex]\frac{2}{3x}[/tex]
Cross- multiply
3x = 12 ( divide both sides by 3 )
x = 4
As a check
Substitute x = 4 into the equation and if both sides are equal then it is the solution.
left side
[tex]\frac{2}{12}[/tex] + [tex]\frac{1}{6}[/tex] = [tex]\frac{1}{6}[/tex] + [tex]\frac{1}{6}[/tex] = [tex]\frac{2}{6}[/tex] = [tex]\frac{1}{3}[/tex]
right side
[tex]\frac{4}{12}[/tex] = [tex]\frac{1}{3}[/tex]
Both sides are equal hence x = 4 is the solution