Respuesta :

Answer:

[tex]\left[\begin{array}{ccc}48&0&6\\4&-24&28\end{array}\right][/tex]

Step-by-step explanation:

4C implies that we multiply each element in C by the constant 4.

12*4 = 48

0*4 = 0

(3/2)*4 = 6

This will be the new elements on top

1*4 = 4

-6 * 4 = -24

7 * 4 = 28

This will be the new elements at the bottom. The required matrix 4C is thus;

[tex]\left[\begin{array}{ccc}48&0&6\\4&-24&28\end{array}\right][/tex]

Answer:

The required matrix is:

[tex]4C=\left[\begin{array}{ccc}48&0&6\\4&-24&28\end{array}\right][/tex]

Step-by-step explanation:

The matrix given is:

[tex]C=\left[\begin{array}{ccc}12&0&3/2\\1&-6&7\end{array}\right][/tex]

We need to find 4C which means we need to multiply the matrix C with 4. Every entry of matrix will be multiplied by 4.

[tex]4C=\left[\begin{array}{ccc}4*12&4*0&4*3/2\\4*1&4*-6&4*7\end{array}\right][/tex]

Solving:

[tex]4C=\left[\begin{array}{ccc}48&0&12/2\\4&-24&28\end{array}\right]\\4C=\left[\begin{array}{ccc}48&0&6\\4&-24&28\end{array}\right][/tex]

SO, the required matrix is:

[tex]4C=\left[\begin{array}{ccc}48&0&6\\4&-24&28\end{array}\right][/tex]

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