Find the lateral area of this pyramid whose base is a regular hexagon with a side length of 3cm and whose slant height is 12cm.

Answer:
108 cm²
Step-by-step explanation:
The lateral area of this pyramid is the addition of the six triangle areas formed on its lateral side.
The area of each triangle is:
Area = (1/2)*side*slant
Area = (1/2)*3*12 = 18 cm²
Then the lateral area is 6*18 = 108 cm²