Question

Will mark Brainliest. Given ƒ(x) = 3x - 1 and g(x)= -x + 6, find ƒ(-2) + g(5).

A.) -6
B.) 6
C.) 8

Answer 1

1. Plug in " -2 " into f

f(-2) = 3 (-2) - 1

f(-2) = -6 - 1

f(-2) = -7

2. Plug in "5" into g

g(5) = -(5) + 6

g(5) = -5 + 6 = 1

3. Add what you got when you solved for f(-2) and g(5) together

f(-2) + g(5) = ?

f(-2) + g(5) = -7 + 1

f(-2) + g(5) = -6

Your answer is A

Don't forget to vote brainliest! I hope I helped! :)

Answer 2

F(x)= 3x -1

G(x)= -x + 6

F(-2) + g(5)= ?

F(-2)= 3(-2) -1

F(-2)= -6 -1

F(-2)= -7

G(5)= -5 + 6

G(5)= 1

F(-2) + g(5) =

-7 + 1 = -6

A) -6