Answer:
The solution to this system is (-2,1)
Step-by-step explanation:
The given system of equations is;
[tex]-3x-4y=2[/tex]...eqn1
and
[tex]-5=5x+5y[/tex]....eqn2
We make y the subject of the second equation to get:
[tex]-5y=5x+5[/tex]
[tex]\implies y=-x-1[/tex]...eqn3
We put eqn3 into eqn1 to get;
[tex]-3x-4(-x-1)=2[/tex]
We expand to get:
[tex]-3x+4x+4=2[/tex]
[tex]-3x+4x=2-4[/tex]
Simplify both sides to get:
[tex]x=-2[/tex]
Put x=-2 into eqn3
[tex]\implies y=--2-1[/tex]
[tex]\implies y=1[/tex]
The solution to this system is therefore (-2,1)