Answer:
The length of the diagonal of a poster board is [tex]35.6\ in[/tex]
Step-by-step explanation:
Let
x----> the length of the diagonal of a poster board
we know that
Applying the Pythagoras Theorem
[tex]x^{2}=22^{2}+28^{2} \\ \\x^{2}=1,268\\ \\x=35.6\ in[/tex]
Answer:
The length of the diagonal of a poster board is 35.6 inches.
Step-by-step explanation:
To find : What is the length of the diagonal of a poster board with dimensions 22 inches by 28 inches?
Solution :
The dimensions of a poster board is
Length = 22 inches
Breadth = 28 inches
The diagonal is given by,
[tex]D=\sqrt{L^2+B^2}[/tex]
[tex]D=\sqrt{22^2+28^2}[/tex]
[tex]D=\sqrt{484+784}[/tex]
[tex]D=\sqrt{1268}[/tex]
[tex]D=35.60[/tex]
Therefore, the length of the diagonal of a poster board is 35.6 inches.
