Answer:
[tex]1.16\cdot 10^{-7} N[/tex]
Explanation:
The force of gravity between two objects is given by:
[tex]F=G\frac{m_1 m_2}{r^2}[/tex]
where
G is the gravitational constant
m1, m2 are the masses of the two objects
r is their separation
In this problem, we have
m1 = m2 = 1170 kg is the mass of each car
r = 28 m is their separation
Substituting,
[tex]F=(6.67\cdot 10^{-11} )\frac{(1170 kg)^2}{(28 m)^2}=1.16\cdot 10^{-7} N[/tex]
Force is the product of mass and acceleration. The Force between the two-car is 1.1646 x 10⁻⁷ N.
Force can be defined as an influence that can change the motion of an object. It can be given by the formula,
F = m x a
Given to us
Masses of the car, m = 1170 kg
Distance between the car, d = 28 m
We know that according to the force of gravity,
[tex]F = G\dfrac{m_1m_2}{d^2}[/tex]
G = gravitational constant (6.67 × 10⁻¹¹ N·m²/kg²),
m₁ = mass of object 1
m₂ = the mass of object 2
d = distance between two objects
Substitute the values,
[tex]F = (6.67 \times 10^{-11})\dfrac{1170 \times 1170}{28^2}\\\\F = 1.1646 \times 10^{-7}\ N[/tex]
Hence, the Force between the two-car is 1.1646 x 10⁻⁷ N.
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